chocolate chip cookies are Poisson distributed

I asked for examples of things that are Poisson distributed in class. One student said the number of chocolate chips in a cookie are Poisson distributed. He’s right.

Here is the intuition of when you have a Poisson distribution. First, you should have a counting process where you are interested in the total number of events that occur by time t or in space s.  If each of these events is independent of the others, then the result is a Poisson distribution.

Let’s consider the Poisson process properties of a chocolate chip cookie. Let N(t) denote the number of chocolate chips in a cookie of size t. N(t) is a Poisson process with rate y if all four of the following events are true:

1) The cookie has stationary increments, where the number of chocolate chips in a cookie is proportional to the size of the cookie. In other words, a cookie with twice as much dough should have twice as many chocolate chips (N(t) ~ Poisson (y*t)). That is a reasonable assumption.

2) The cookie has independent increments. The number of chocolate chips in a cookie does not affect the number of chocolate chip cookies in the next cookie.

3) A cookie without any dough cannot have any chocolate chips (N(0)=0)).

4) The probability of finding two or more chocolate chips in a cookie of size h is o(h). In other words, you will find at most one chocolate chip in a tiny amount of dough.

All of these assumptions appear to be true, at least in a probabilistic sense. Technically there may be some dependence between chips if we note that bags of chocolate chips have a finite population (whatever is in the bag). There is some dependence between the number of chocolate chips in one cookie to the next if we note that how many chips we have used thus far gives us additional knowledge about how many chips are left. This would violate the independent increments assumption. However, the independence assumption is approximately true since the frequency of chocolate chips in the cookie you are eating is roughly independent of the frequency of chocolate chips in the cookies you have already eaten. As a result, I expect the Poisson is be an excellent approximation.

Picture courtesy of Betty Crocker


5 responses to “chocolate chip cookies are Poisson distributed

  • Tom Hughes (@tmcmh)

    I’m not sure about your first assumption — that a cookie with 2x dough should have 2x chips. That would not be the case if you were, say, optimally filling beach balls with ping-pong balls. Of course it would be entirely true if you were following a recipe which states a chip/dough ratio that you scale up (or down — but don’t do that). For me, the point of making more dough is to put in MANY more chips… In case you’re wondering, my preferred chocolate chips are Ghirardelli’s semi-sweet and bittersweet, mixed.

  • Laura Albert McLay

    Thanks for the comment, Tom.

    The first assumption is saying if you take a scoop of dough twice as big as the last scoop of dough, the cookie with the big scoop will have twice as many chips as the smaller scoop. It’s identical to following a recipe which states a chip/dough ratio that you scale up or down.

    And yes, Ghirardelli chocolate chips are the best 🙂

  • Brian Borchers

    If the number of chocolate chips in a batch of dough are fixed and the number of cookies in a batch are fixed, the number of chocolate chips in the cookie should follow a binomial distribution. However, because the Poisson distribution is the limiting case of a binomial distribution when N is big and p is small, the Poisson distribution is probably an adequate model.

    You could always run the experiment, gather some data (I’m afraid that the cookies would have to be consumed during the experiment) and perform a statistical test of goodness of fit (Chi-squared is easy to do.)

  • vdmedragon

    Reblogged this on My stuffs.

  • hungryheathen

    Those assumptions, are good enough for me, ohhh…
    Cookie, cookie, cookie starts with ‘C’!

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